Solution: how many students passed in both subjects?

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Maryam Hauck asked a question: Solution: how many students passed in both subjects?
Asked By: Maryam Hauck
Date created: Sun, May 30, 2021 8:47 AM
Date updated: Wed, Jan 19, 2022 2:21 PM

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🎓 N class of 100 students 50 students passed in mathematics and 70 passed in english 5 students failed in both mathematics and english how many students passed in both the subjects?

Using set theory let A contain the students who failed mathematics (50) and B contain the students that failed English (30). Now set A and B intersect so they share the same students (5). Therefore the students who passed both subjects is the complement of the union of the sets. ~(AUB)=~(A+B-AintersectB)=100-(50+30-5)=25 students.

🎓 In a class of 150 students 70 students passed in physics 90 passed in statistics and 10 students failed in both the subjects. how many students passed in at least one subject?

140

🎓 How many students passed iit jee2012?

Around 5000 students passed IIT JEE 2012. Indian Institute of Technology's are the top colleges for engineering in India.

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The number of students who passed in both subjects is 28.

If none of the examinees fails both subject and there are 4 examinees who pass both subjects, find the number of examinees from that school who took the examinations. Problem Answer: There are 28 examinees from a certain school who took the examinations.

Number of students passed in both subjects n(MnS) = 10. Number of students passed in science n (S) = 28. From this, we have to find the number of students who passed in mathematics. n (M U S) = n (M) + n (S) - n (M n S) 50 = n (M) + 28 - 10. 50 = n (M) + 18. Subtract 18 on both sides. 50 - 18 = n (M) + 18 - 18. n (M) = 32. So, the number students passed in Mathematics is 32. Method 2 : Let "x" be the number of students passed in Mathematics. By representing the given details in venn diagram ...

Now 50 students passed in maths + 70 students for english =120 which is different from value we got previously and this could only possible if there are (120-95) students that passed in both the subjects and we are calculating them two times when adding 50 & 70.

No of students passed In both subjects =20. No of STUDENTS passed in mathematics =40+20=60. percentage of students passed In both subjects =20percent. Percentage of students who passed In MATHEMATICS =60percent. This problem can be solved Using Venn diagrams

n (A ∩ B) = number of students who passed both subjects n (A ∪ B) = number of students who passed in at least one of the subjects As we know, n (A ∪ B) = n(A) + n(B) – n (A ∩ B)

Click here👆to get an answer to your question ️ In an examination, 80% students passed in Mathematics, 72% passed in Science and 13% failed in both the subjects. If 312 students passed in both the subjects, find the total number of students who appeared in the examination.

Click here👆to get an answer to your question ️ Out of 100 students 50 fail in English and 30 in Maths. If 12 students fail in both English and Maths, then the number of students passing both the subjects is

in an examination, 60 candidates passed science or maths.if 6 passed both subjects and 9 more passed maths than science.find the number of candidates who passed in each subject Reply IBRAHIM YAKUBU says:

The number of students who like watching at least two of the given games=(number of students who like watching only two of the games) +(number of students who like watching all the three games)= (12 + 13 + 14 + 15)% i.e. 54% of 500 = 270.

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